Question

Reet sells two radios sets for rs2288 each on one he gains
10%and on other he loses 10% find her gain or loss percent

Answer 1

Given :

Selling price of each radio : ₹2288

Gain percent of first radio : 10%

Loss percent of second radio : 10%

To find :

The total gain or loss percentage.

Solution :

First, we should find the cost price of both radios.

Cost price of first radio :

$\sf \dashrightarrow \dfrac{100}{(100 + Gain\%)} \times SP$

$\sf \dashrightarrow \dfrac{100}{(100 + 10)} \times 2288$

$\sf \dashrightarrow \dfrac{100}{110} \times 2288$

$\sf \dashrightarrow \dfrac{10}{11} \times 2288$

$\sf \dashrightarrow \dfrac{10 \times 2288}{11} = \dfrac{22880}{11}$

$\sf \dashrightarrow \cancel \dfrac{22880}{11} = 2080$

Cost price of second radio :

$\sf \dashrightarrow \dfrac{100}{(100 - Loss\%)} \times SP$

$\sf \dashrightarrow \dfrac{100}{(100 - 10)} \times 2288$

$\sf \dashrightarrow \dfrac{100}{90} \times 2288$

$\sf \dashrightarrow \dfrac{10}{9} \times 2288$

$\sf \dashrightarrow \dfrac{10 \times 2288}{9} = \dfrac{22880}{9}$

$\sf \dashrightarrow \cancel \dfrac{22880}{9} = 2542.22$

Now, we should find the total cost price and selling price.

Total cost price :

$\sf \dashrightarrow 2080 + 2542.22$

$\dashrightarrow$₹$\sf 4622.22$

Total selling price :

$\sf \dashrightarrow 2288 + 2288$

$\dashrightarrow$₹$\sf 4576$

Now, we can find the loss rupees.

Loss rupees :

$\sf \dashrightarrow 4622.22 - 4576$

$\dashrightarrow$₹$\sf 46.22$

Now, we can find the loss percentage.

Loss percentage :

$\sf \dashrightarrow \dfrac{Loss}{Cost \: price} \times 100$

$\sf \dashrightarrow \dfrac{46.22}{4622.22} \times 100$

$\sf \dashrightarrow \dfrac{4622}{462222} \times 100$

$\sf \dashrightarrow \dfrac{4622 \times 100}{462222} = \dfrac{462200}{462222}$

$\sf \dashrightarrow \cancel \dfrac{462200}{462222} = 0.99$

Hence, the total loss percentage is 0.99%.