Question

REFER THE ATTACHMENT

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Answer 1

Answer:

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Step-by-step explanation:

Answer 2

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Area o a triangle = 5sq.unit

Two vertices of △le,A(2,1),B(3,−2),C(x,y)

Third vertex lies on the line y=x+3→(1)

Area 21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]=5⇒[2[−2−y]+3[y−1]+x(1+2)]=10−4−2y+3y−3+3x=10⇒y+3x=17→(2)

Solving (1) and (2)

∴4x=14y+3x=17y−x=3⇒x=27y=27+3=213∴(x,y)=(27,213)