Question

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Answer 1

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Answer 2

Explanation:

Hey mate..,,

Eq. (SHM) is

$a = - bx$

So after Rearraging properly

$\frac{a}{x} = - b$

Now taking reciprocal

$\frac{x}{a} = \frac{1}{ - b}$

Where

a= Acclearation

x= displacement

b= constant

By using formula that it

Time peroid=

$= > 2\pi \: \sqrt{ \frac{displacement}{accleration} } \\ \\ = > 2\pi \sqrt{ \frac{1}{b} } \\ = > \frac{2\pi}{ \sqrt{b} }$

Therefore the period of the particle is

[tex] \frac{2\pi}{ \sqrt{b} } [/tex

This will help