Question

Refer to the attachment for the question.

Answer 1

Answer:

Step-by-step explanation:

let us assume a= $\sqrt{3$

and d as common ratio then:-

ad=3

replacing a's value

d$\sqrt{3$=3

d=$\sqrt{3$

So;-

ad^n=729

$\sqrt{3$x$\sqrt{3$^n=

$\sqrt{3$^(n+1)=$\sqrt{3$^12

so:-

n+1=12

n=11

hence it is the llth term of the GP

Please mark me as the brainliest

Answer 2

Step-by-step explanation:

hope you will understand