Question

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Answer 1

Answer:

Initial velocity u=0 m/s

Final velocity v=7.10 m/s

Distance covered s=35.4 m  

Acceleration a=?

Using the equation of motion:

v²=u²+2as

(7.10)²=0+2a x 35.4

A= 7.10²/2 x 35.4

= 0.712 ms-²

Explanation:

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Answer 2

Answer:

• -0.71 m/s².

Explanation:

Given :

• Distance covered (s) = 35.4 m
• Initial velocity (u) = 7.10 m/s
• Final velocity (v) = 0 m/s

To find :

• Acceleration (a)

Solution :

Using Kinematics:

⇒ v² - u² = 2as

Substituting:

⇒ 0² - 7.10² = 2a(35.4)

⇒ 0 - 50.41 = 70.8a

⇒ a = -50.41/70.8

⇒ a = -0.71 m/s²

∴ The acceleration of the bike is -0.71 m/s or the retardation of the bike is 0.71 m/s².