Question

Refraction through glass slab​

Answer 1

Answer:

refrection of light means diversion of light while passing from one medium to another

Answer 2

Refraction through glass slab

$\setlength{\unitlength}{1cm}\begin{picture}(12,12)\put(0,0){\framebox(9,5)}\multiput(4,6.5)(2,-5){2}{\line(0,-1){3}}\thicklines\qbezier(4,5)(4,5)(6,0)\qbezier(1.5,7.5)(3,6)(4,5)\qbezier(6,0)(6,0)(8.5,-2.5)\multiput(4,5)(0.5,-0.5){14}{\line(1,-1){0.4}}\linethickness{0.24mm}\qbezier(3.5,5.5)(3.7,5.9)(4,5.7)\qbezier(6,-0.6)(6.3,-0.85)(6.5,-0.5)\qbezier(4,4)(4.3,3.8)(4.38,4.1)\qbezier(6,1)(5.8,1.2)(5.62,0.9)\put(2.5,6.5){\line(-1,0){0.4}}\put(2.5,6.5){\line(0,1){0.4}}\put(7.5,-1.5){\line(-1,0){0.4}}\put(7.5,-1.5){\line(0,1){0.4}}\qbezier(5,2.5)(5,2.5)(4.6,2.7)\qbezier(5,2.5)(5,2.5)(5.2,2.9)\thinlines\qbezier(8,-2)(8,-2)(9.5,-0.5)\put(3.8,6.7){\bf M}\put(3.8,3){\bf M'}\put(5.8,1.8){\bf N}\put(5.8,-2){\bf N'}\put(1,7.7){\bf A}\put(4.3,5.3){\bf B}\put(5.4,-0.5){\bf C}\put(7.5,-2.4){\bf D}\put(9.8,-0.5){\rm E}\put(0.5,5.5){\sf AIR}\put(0.5,2.5){\sf GLASS}\put(0.5,-0.8){\sf AIR}\put(3.5,6){\bf i}\put(6.4,-1.2){\bf e}\linethickness{0.24mm}\qbezier(4,3.85)(4.3,3.7)(4.4,3.9)\qbezier(6,1.15)(5.8,1.3)(5.6,1.1)\put(5,5.5){\sf DE=Lateral Displacement}\end{picture}$

Note : Kindly, See the answer through web .