Question

Refractive index of glass is 1.5. If the speed of light in vacuum is 3 X 108
m/s, find velocity of light in medium.​

Answer 1

Step-by-step explanation:

we know that refractive index n=speedoflightinmediumspeedoflightinvacuum

where c=3×108m/s

1.5=vc

v=1.53×108

v=2×108m/s

For critical angle we will use snell's law

C is critical angle

nglasssinC=nairsin90     nair=1

sinC=nglass1=1.51

C=41.8

Answer 2

The velocity of light in the medium is

$2 \times {10}^{8} m {s}^{ - 1}$

Given:

The Refractive index of glass is 1.5

speed of light in a vacuum is 3×10^8 m/s.

To Find:

We need to find the velocity of light.

Solution:

As we know that

$refractive \: index = \frac{speed \: of \: light \: in \: vacuum}{velocity \: of \: light}$

$1.5 = \frac{3 \times {10}^{8} }{x}$

$x = \frac{3 \times {10}^{8} }{1.5}$

$x = 2 \times {10}^{8} m {s}^{ - 1}$

Therefore, the velocity of light is 2×10^8m/s.

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