Refractive index of Ice is 1.33 and that of water is 1.33 calculate refractive index of ice with respect of water
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Answer:
The refractive index of ice with respect to water under given information would be 1(one).
Because the required refractive index would be division of refactive index of ice by refactive index of water. But since both are equal to 1.33 then refractuve index of ice with respect to water becomes 1 (one).
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A material's refractive index is the ratio of light velocity in a vacuum to that in the material.
Refractive index of water (water n air)= 1/3
Refractive index of glass (glass n air) = 1/3
N= c/v, where n is the index of refraction value of a material, c is the speed of light in a vacuum, and v is the overall speed of light in a material.
Thus,
n = refractive index c = 299792458 and v = phase velocity of light in the medium
V = c/n
v = 299792458/1.33
v = 225 .407 . 863.2 m/s
Therefore, the optical density of ice will be less than that of water as light travels through ice faster than travelling through water.