Math, asked by avanthikaavi6634, 8 months ago

There are 40 coins placed on a table. 20 coins are heads up and rest 20 are tails up mixed randomly. mike puts on a blindfold and decides to create two piles of coins from these 40 coins, such that each set has the same number of coins with heads up and tails up. he can only move or flip the coins as he is unable to see them.how does he create these two groups of coins?

Answers

Answered by amitnrw
18

Mike has to flip all the coins of one of the Pile

Step-by-step explanation:

There are 40 coins placed on a table. 20 coins are heads up and rest 20 are tails up mixed randomly.

Mike Creates two piles each of 20 Coins

Now let Say Pile  A  has  -  X  Heads

Then Pile A will have 20- X    Tails

now in pile B

Number of Head = 20 - X Heads

Number Of Tails = 20 - (20 - X)  = X   Tails

                        Heads          Tails

Pile A              X                   20-X

PileB               20-X              X

if we just notice that number of Heads & Tails are interchanged in Pile A & B

if Mike flip all coins of one pile  then number of Heads & Tails will be exchanged

let say Pile B is Flipped  then

20 - X  heads  will become 20- X tails

& X tails will become  X heads

                        Heads          Tails

Pile A              X                   20-X

PileB               X                   20-X

Both Piles having same head & same Tail

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