Question

Refractive index of prism is 7/3 and the angle of the prism is 600 digger
. the minimum angle of incident of the ray that will be transmitted through the prism is

Answer 1

Answer:

A ray is projected on face LM of the prism gets refracted from the two faces of the prism and finally emerges out of it.

For minimum i, the emergent ray must graze on the face LN i-e. e=90

o

Using Snell's law for face LN, n

2

sinr

2

=n

1

sine

3

7

sinr

2

=1×sin90

o

This gives r

2

=40.89

o

As A=r

1

+r

2

,A=60

o

r

2

=19.11

o

Using snell's law for face LN, 1×sini=

3

7

×sin19.11

o

This gives i=30

o

Explanation:

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