Refractive index of prism is root 7/3 an the angle of prism is 60
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Step-by-step explanation:
=> It is given that,
Refractive index of prism, μ = √7/3
An the angle of prism, A = 60 °
=> Critical angles:
θc = Sin⁻¹ (1/μ)
= Sin⁻¹ (3/7)
= 40.9°
=> The angle the light ray is refracted to relative to the normal, r :
r₂ = θc = 40.9°
r₁ = A - θc
= 60° - 40.9°
= 19.1°
=> According to snell's law, Refractive index :
μ = sin i₁ / sin r₁
√7/3 = sin i₁/sin r₂
sin i₁ = √7/3 sin r₂
= √7/3 sin 40.9°
i₁ = 30°
Thus, the limiting angle of incidence of a ray that will be transmitted through the prism is approximately 30°.
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