Question

Refractive index of prism is root 7/3 an the angle of prism is 60

Answer 1

Answer:

Step-by-step explanation:

=> It is given that,

Refractive index of prism, μ = √7/3

An the angle of prism, A = 60 °

=> Critical angles:

θc = Sin⁻¹ (1/μ)

= Sin⁻¹ (3/7)

= 40.9°

=> The angle the light ray is refracted to relative to the normal, r :

r₂ =  θc = 40.9°

r₁ = A -  θc

= 60° - 40.9°

= 19.1°

=> According to snell's law, Refractive index :

μ = sin i₁ / sin r₁

√7/3 = sin i₁/sin r₂

sin i₁ = √7/3 sin r₂

= √7/3 sin 40.9°

i₁ = 30°

Thus, the limiting angle of incidence of a ray that will be transmitted through the prism is approximately 30°.