refractive index of water is 1.33 calculate the angle of polarisation for light reflected from the surface of a lake (tan-¹1.33=53°)
Answers
Angle of polarization for given light is 53°.
Angle of polarization is also known as Brewster's angle. It is defined as "an angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection."
Angle of polarization is calculated by the formula -
tan theta = n2/n1
In this formula, n1 is the refractive index of incident ray medium and n2 is the refractive index of second medium, in this case, water.
Incident ray medium for this question will be air, which has refractive index equal to 1.
Now, putting values in formula -
tan theta = 1.33/1
tan theta = 1.33
theta = tan^-1(1.33)
theta = 53°
Thus, angle of polarization is equal to 53°
Answer:
The refractive index for water is 1.33. Calculate the angle of refraction for a ray of light
incident at polarizing angle