Physics, asked by jagdishjambe1201, 9 months ago

Refrigerator of rating 400w for 10 hour daily. Calculate the electricity bill the household for month of June. If the cost per unit of is 3 .00

Answers

Answered by Anonymous
9

GiveN :

  • Power consumed by Refrigerator = 400 W
  • Time = 10 hours daily.
  • Cost is Rs. 3 per unit

To FinD :

  • Electricity bill in month of June

Solution :

As we know that the electricity is measured in KWh which is Kilo Watt Hour. And 1 KWh is called as 1 unit.

So, we will fist calculate the number of units each day,

⇒Power/1000 * Time

⇒400/1000 * 10

⇒0.4*10

⇒4 kWh

➠ Unit consumed in each day is 4 units

\rule{150}{0.5}

Now, units consumed in Month of June :

⇒Unit of 1 day * 30

⇒4 * 30

⇒ 120 Units

➠ Units consumed in Month of June is 120 Units

______________________

Now, we have to calculate the bill if cost for each unit is Rs. 3

⇒Bill = 120 * 3

⇒Bill = 360

➠ Bill in month of June is Rs. 360

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