Physics, asked by jagdishjambe1201, 10 months ago

Refrigerator of rating 400w for 10 hour daily. Calculate the electricity bill the household for month of June. If the cost per unit of is 3 .00

Answers

Answered by Anonymous
9

GiveN :

  • Power consumed by Refrigerator = 400 W
  • Time = 10 hours daily.
  • Cost is Rs. 3 per unit

To FinD :

  • Electricity bill in month of June

Solution :

As we know that the electricity is measured in KWh which is Kilo Watt Hour. And 1 KWh is called as 1 unit.

So, we will fist calculate the number of units each day,

⇒Power/1000 * Time

⇒400/1000 * 10

⇒0.4*10

⇒4 kWh

➠ Unit consumed in each day is 4 units

\rule{150}{0.5}

Now, units consumed in Month of June :

⇒Unit of 1 day * 30

⇒4 * 30

⇒ 120 Units

➠ Units consumed in Month of June is 120 Units

______________________

Now, we have to calculate the bill if cost for each unit is Rs. 3

⇒Bill = 120 * 3

⇒Bill = 360

➠ Bill in month of June is Rs. 360

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