Question

Registers of 5,10, 15 ohms are connected in series find the equivalent resistance and current if the potential difference is 5 volt

Answer 1

• R1=5ohm
• R2=10ohm
• R3=15ohm

We know

$\boxed{\sf R=R_1+R_2+R_3}$

$\\ \sf\longmapsto R=5+10+15$

$\\ \sf\longmapsto R=30\Omega$

• Potential Difference=V=5V
• Current=I=?

Using ohms law

$\boxed{\sf \dfrac{V}{I}=R}$

$\\ \sf\longmapsto I=\dfrac{V}{R}$

$\\ \sf\longmapsto I=\dfrac{5}{30}$

$\\ \sf\longmapsto I=0.16A$

Answer 2

Answer:

$\odot \: \green{ \sf equivalent \: resistance \: \: R_{eq} = 30\Omega} \\ \\ \odot \: \orange{ \sf \: current \: I = 0.167 \: A \: } \:$

Explanation:

Given,

$\sf \: resistance \: R_1 = 5\Omega \\ \sf \: resistance \: R_2 = 10\Omega \\ \sf \: resistance \: R_3 = 15\Omega \\ \sf \: voltage \: \: v = 5v$

To find :

★ Equivalent resistance $</strong><strong>R</strong><strong>_</strong><strong>{</strong><strong>eq</strong><strong>}</strong><strong>$

★ Current = I

Formula :

1) When n resistance are in series:

$\green{\boxed{R_{eq}=R_1+R_2+R_3+...+R_n}}$

2) V = IR

Solution :

1)

all resistors are connected in series.

So,

$\sf \: R_{eq} = R_1 + R_2 + R_3 \\ \sf \: \: \: \: \: \: \: \: = 5 + 10 + 15 \\ \sf \: \: \: \: \: \: \: \: = 30\Omega \: \\ \\ \green{ \sf equivalent \: resistance \: \: R_{eq} = 30\Omega}$

2)

$\sf \: V = IR_{eq} \\ \implies \: I = \frac{V }{R_{eq}} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \: = \frac{5}{30} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf = 0.167 \: A \: \\ \\ \orange{ \sf \: current \: I = 0.167 \: A \: }$