Question

Regular hexagon with side length a is shown in
fig. Find E? ​

Answer 1

Answer:

kQ/a^2

Explanation:

'E' is in the outward direction since the charges are positive. Now, 'E' resultant of the single Qs will be towards point A whose magnitude will be kQ/a^2. Now, 'E' due to charge 2Q is 2kQ/a^2 and in the direction opp. to point A. So if we take direction of point A to be -ve and direction opp. to point A to be +ve then, 2kQ/a^2 - kQ/a^2 = kQ/a^2