Rekha and Meetha can wear a sweater in 12 days meeta and Payal in 15 days Payal and Rekha in 20 days in how many days will they weave if they work together in how many days will each of them if they will it alone
Answers
R + M = 12 days
In 1 day, they can weave 1/12 of a sweater
M + P = 15 days
In 1 day, they can weave 1/15 of a sweater
P + R = 20 days
In 1 day, they can weave 1/20 of a sweater
Together:
2R + 2M + 2P = 1/12 + 1/15 + 1/20
2R + 2M + 2P = 1/5 of a sweater
R + M + P = 1/5 ÷ 2
R + M + P = 1/10 of a sweater
Find the number of days needed if 3 of them weave together:
1/10 of a sweater = 1 day
10/10 of a sweater = 1 x 10
1 sweater = 10 days
Answer: They can weave a sweater in 10 days.
R + M + P = 1/10 of a sweater
R + M = 1/12
P = 1/10 - 12
P = 1/60 of a sweater
Answer: Number of days Payal needed = 60 days
R + M + P = 1/10 of a sweater
M + P = 1/15
R = 1/10 - 1/15
R = 1/30
Answer: Number of days Rekha needed = 30 days
R + M + P = 1/10 of a sweater
P + R = 1/20
M = 1/10 - 1/20
M = 1/20
Answer: Number of days Meetha needed = 20 days