Math, asked by tabbymykitten, 9 months ago

Rekha borrowed rupees 40000 for 3 years at 10% per annum compound interest calculated the interest paid by her for the second year​

Answers

Answered by Hanusuha
0

Rupees borrowed = principal =P = Rs 40000

rate of interest = r = 10% p.a

number of times interest paid =n = 2(2years)

amount at the end of 2 year = A = P[(100+r)/100]^n

= 40000[(100+10)/100]^2

= 40000*110/100 *110/100

=4*110*110

A=Rs48400

interest paid for 2 years = A -P

=48400-40000

=Rs8400

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