Question

Rekha is 24 years older than her daughter Ishita.After 8 years she will be twice as old as Ishita.Find their present ages..​

Answer 1

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$<b><I>Let us take the present age of Rekha's daughter be x.</b>$

Then , the age of Rekha = x + 24.

Age of her daughter after 8 years = x + 8.

Age of Rekha after 8 years = x + 24 + 8 = x + 32.

So,

ATQ, 2(x + 8) yrs.= x + 32 yrs.

or 2x + 16 = x + 32.

or 2x - x = 32 - 16.

Therefore x = 16.

$<b>Therefore present age of Rekha's daughter = x = 16years. Therefore age of Rekha = x + 24 = 24 + 16 = 40years .$

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Answer 2

let the present age of ishita be x and that of rekha be x+24
after 8 years age of ishita be x+8
and rekha be x +24+8 = x + 32
so according to question
2(x+8) = x+32
2x + |6 = x+ 32
x = |6
ishita age is |6 and
rekha age is |6 +24= 40