Rekha swims in a 90m long pool.She covers 180m in one minute by swimming from one end to the other end back along the same straight path .Find the average speed and average velocity of rekha.
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Length of the pool: 90m
Average speed:
Speed= Distance/Time
speed=180/60
speed=30 m/s
Velocity:
velocity=displacement/time
displacement=0( Since she comes back to the same place)
velocity=0
Happy to help
Average speed:
Speed= Distance/Time
speed=180/60
speed=30 m/s
Velocity:
velocity=displacement/time
displacement=0( Since she comes back to the same place)
velocity=0
Happy to help
Answered by
8
Distance covered by Rekha = 180 m
Displacement = 0 ( As Rekha came back to the starting point ).
Time taken = 1 min = 60 s.
Average speed = Total distance covered ÷ Total time taken
= 180 m ÷ 60 s
= 3 m/s.
Average velocity = Displacement ÷ Time taken
= 0 m ÷ 60 s
= 0 .
Displacement = 0 ( As Rekha came back to the starting point ).
Time taken = 1 min = 60 s.
Average speed = Total distance covered ÷ Total time taken
= 180 m ÷ 60 s
= 3 m/s.
Average velocity = Displacement ÷ Time taken
= 0 m ÷ 60 s
= 0 .
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