Question

Relation between brewster angle and critical angle

Answer 1

Sinc=cot ip because n=1/sinc & n=tanip

Answer 2

Hey Dear,

◆ Answer -

sinθc = 1/tanθb

● Explanation -

Brewster's angle is given by formula -

θb = arctan(n2/n1)

tanθb = n2/n1

Critical angle is given by formula -

θc = arcsin(n1/n2)

sinθc = n1/n2

sinθc = 1/(n2/n1)

But we have, tanθp = n2/n1, thus

sinθc = 1/tanθb

We can calculate these angles from each other using -

θc = arcsin(1/tanθb)

θc = arcsin(1/tanθb)

Thanks dear...