Question

relation between electric field and potential gradient

Answer 1

Hi friend,

The relationship between electric field and potential gradient is given by

E=-dv/DX

Where
E=Electric field
dv= change in potential difference (or) gradient

DX=differentiate with respect to "x".

NOTE:-
( The negative sign indicates that the direction of potential is opposite to the electric field).

Hope this helps you..☺☺

Answer 2

AnswEr:—

VA - VB = w/qo

dv = w/qo ....(1)

dv → potential difference

w = Fdr cos 180°

= (qo)E)dr (-1)

= - qo E dr ...(2)

putting (2) in (1)

dv = -qo Edr/qo

E = -dv/dr

$\rule{200}2$

Related Information:—

• electric potential difference:- VA - VB = l/qo, w- work done in moving test charge from B to A against Coulomb's repulsion.
• It's unit is Joule/coulomb or volt.
• It is a scalar quantity.

$\rule{200}2$