Question

relation between solubility and solubility product of CaF2

Answer 1

caf2= ca2+ +f-

Ksp =x^3

Answer 2

Hey brainly user

Here is your answer

Solubility product :

The product of the concentration of the cation And the anion in a saturated solution of a salt at room temperature is called solubility product

Solubility :The amount of solution in which the solute is get dissolved in the slovent is called

CaF2--------» Ca^+2 + 2F^-2

Ksp= [s][2s]^2

Ksp=4s^3

$s = \sqrt[3]{ \frac{ksp}{4} }$