Question

relation between the particle's situation x and time t is x =at^2 -bt^3. Then what will be the acceleration of the particle after 2 second​

Answer 1

Answer:

Explanation:

DISPLACEMENT OF THE BODY IN TERMS OF TIME(GIVEN):

X=AT²-BT³

DIFFERENTIATING WITH RESPECT TO T

dX/dT =2AT-3BT²                                            [  BUT dX/dT= VELOCITY]

V=2AT-3BT²

AGAIN DIFFERENTIATING WITH RESPECT TO T

dV/dT=2A-6BT                                                 [ BUT dV/dT= ACCELERA-

                                                                                                          TION]

ACCELERATION=2A-6BT

GIVEN T=2

ACCELERATION=2A-12B

ACCELERATION=2(A-6B).

HOPE THIS HELPS.