Relation between universal gravitaional
Constant and the gravitational acceleration on the surface of the earth
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Answered by
1
Answer:
acceleration due to gravity g=GM/R2(square)
Explanation:
Let g be acceleration due to gravity at a planet of mass M and radius R then by newton's law of motion force F is
F= mass*acceleration due to gravity
OR F=m*g. (3.14)
by newton's gravitational law
F=GMm/R2(square) ( 3.15)
from equations (3.14)and (3.15)
GMm/R2(square)=mg
THEN YOU WILL GET THE ANSWER
Answered by
2
acceleration due to gravity g=GM/R2(square)
Explanation:
Let g be acceleration due to gravity at a planet of mass M and radius R then by newton's law of motion force F is
F= mass*acceleration due to gravity
OR F=m*g. (3.14)
by newton's gravitational law
F=GMm/R2(square) ( 3.15)
from equations (3.14)and (3.15)
GMm/R2(square)=mg
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