Relation or similarity Betweeh G ( universal gravitational constant) and g ( acceleration due to Gravity) ?
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Answered by
2
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Good morning ..⏲️⏲️
Your answer is ...⬇️⬇️
☑️G' & ‘g' are related to gravitational force.
☑️G is known as universal gravitational constant. Its numerical value is 6.67 × 10^-11 N-m²/Kg²
☑️g is known as acceleration due to gravity. And its generally numerical value is 9.8 m/s². It is changeable. It is different for place in earth. g = 10 m/s² in Poles.
✴️The relation between ‘G’ & ‘g' :-
✴️According the Newton’s law of gravitation -
F = G M.m / r² -(I)
where M and m are two masses distance between r metre.
By Newton's second law :-
F = mg -(ii)
Where F is force and m is mass and g is acceleration due to gravity.
Now equating equation (i) and (ii) than:-
= mg = G M.m / r²
= g = G M / r² -(iii)
The above equ. (iii) is the relation between ‘G’ and ‘g'.
hope it helps you✌️✌️
#APS☺️☺️
Good morning ..⏲️⏲️
Your answer is ...⬇️⬇️
☑️G' & ‘g' are related to gravitational force.
☑️G is known as universal gravitational constant. Its numerical value is 6.67 × 10^-11 N-m²/Kg²
☑️g is known as acceleration due to gravity. And its generally numerical value is 9.8 m/s². It is changeable. It is different for place in earth. g = 10 m/s² in Poles.
✴️The relation between ‘G’ & ‘g' :-
✴️According the Newton’s law of gravitation -
F = G M.m / r² -(I)
where M and m are two masses distance between r metre.
By Newton's second law :-
F = mg -(ii)
Where F is force and m is mass and g is acceleration due to gravity.
Now equating equation (i) and (ii) than:-
= mg = G M.m / r²
= g = G M / r² -(iii)
The above equ. (iii) is the relation between ‘G’ and ‘g'.
hope it helps you✌️✌️
#APS☺️☺️
Answered by
0
G is the force between two bodies of unit mass separated by a unit distance is known as universal gravitational constant.
Whereas, g is the acceleration produced in a body falling freely under the action of gravitational pull of the Earth is known as acceleration due to gravity or g.
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