Question

Relative lowering of vapour pressure of an aqueous dilute solution of glucose is 0.018. What is the mole fraction of glucose in the solution?

Answer 1

Answer:

answer is 0.018

Explanation:

as relative lowering of vapour pressure is equal to mole fraction of solute.

Answer 2

Mole fraction of glucose = 0.018

The mole fraction of glucose is equal to the relative lowering of vapor pressure.

GIVEN

Relative lowering of vapor pressure = 0.018

TO FIND

Mole fraction of glucose in a solution.

Solution

SOLUTION

We can simply solve the above problem as follows -

According to Raoult's law - At a given temperature, The vapor pressure of solvent containing a non-volatile solute is proportional to the mole fraction of solvent.

So,

Ps = Po × Xa

Where,

Ps = vapor pressure of the solvent

Po = vapor pressure of the solution.

Xa = mole fraction of solvent.

Now,

Ps = Po × Xa

Ps/Po = Xa

Now, let's subtract 1 from both sides -

1- Ps/Po = 1-Xa

Ps - Po/Po = Xs. ( Xs + Xa = 1 )

where,

Xs = Mole fraction of solute.

The value of (Ps - Po/Po) is given - 0.018

So mole fraction of Glucose is 0.018.

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