Question

Remote Sensing satellite of Earth revolves in a circular orbit at a height of 0.25×10^6 m above the surface of the Earth.If earth radius is 6.38×10^6 m and g=9.8 ms -2 then the orbital speed of the satellite is?​

Answer 1

➩Given:-

•Height of a satellite h = 0.25 × 10^6m

• Earth's radius, Re = 6.38 × 10^6m

➩Solution:-

➞For the satellite revolving around the Earth, orbital velocity of the satellite

vo = √GMe/Re = √GMe/ [ Re (1+ h/Re)]

vo = √gRe/1+(h/Re)

➞Substitutes the values of g, Re and h, we get

vo = √60×10^6 m/s

vo = 7.76 × 10^3m/s

vo = 7.76 km/s

∴ The orbital speed of the satellite is 7.76 km/s!

Answer 2

Explanation:

✍️Given:-

•Height of a satellite h = 0.25 × 10^6m

• Earth's radius, Re = 6.38 × 10^6m

✍️Solution:-

➞For the satellite revolving around the Earth, orbital velocity of the satellite

vo = √GMe/Re = √GMe/ [ Re (1+ h/Re)]

vo = √gRe/1+(h/Re)

➞Substitutes the values of g, Re and h, we get

• vo = √60×10^6 m/s
• vo = 7.76 × 10^3m/s
• vo = 7.76 km/s

∴ The orbital speed of the satellite is 7.76 km/s!

hope this helps you ☺️