Question

Removal of oxygen from a substance is called its..
(a) Oxidation
(b) Corrosion
(c) Dehydration
(d) Reduction​

Answer 1

$\huge{ \boxed{ \bf{ \orange{Red} \blue{uct} \orange{ion....}}}}$

♦️ Option D

The Reduction process can be done by 4 methods which are addition of Hydrogen, removal of Oxygen, Removal of an electro negative element or addition of electro positive element.

${\rm{\red{(1) Addition \: of \: Hydrogen}}}$

$\large{\rm{H_2 + S \longrightarrow H_2S}}$

$\large{\rm{Cl_2 + H_2S \longrightarrow 2HCl+S}}$

Hydrogen sulphide when react with chlorine get oxidized to sulphur where as chlorine gets reduced to HCl

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$\large{\rm{H_2 + Cl_2\longrightarrow 2HCl}}$

$\large{\rm{2Na + H_2 \longrightarrow 2NaH}}$

${\rm{\red{(2) Removal \: of \: Oxygen}}}$

$\large{\rm{H_2O + C \longrightarrow CO+H_2}}$

In this case,water has been reduced to hydrogen by the removal of oxygen.

$\large{\rm{ZnO+ H_2\longrightarrow Zn+H_2O}}$

Zinc Oxide reduced to Zinc by removal of Oxygen.

$\large{\rm{CuO+H_2 \longrightarrow Cu+H_2O}}$

${\rm{\red{(3) Removal \: of \: Electronegative \:element}}}$

$\large{\rm{Cl_2 + Mg\longrightarrow MgCl_2}}$

$\large{\rm{I_2 + Hg \longrightarrow HgI_2}}$

In the above reaction, Cl2 is reduced to MgCl2 and I2 is reduced to HgI2

${\rm{\red{(4) Addition \: of \: Electropositive\: element}}}$

$\large{\rm{2FeCl_2\longrightarrow 2Fe+Cl_2}}$

$\large{\rm{FeS \longrightarrow Fe+S}}$

In the above reactions, change of FeCl3 and FeS to FeCl2 and Fe respectively is example of reduction.

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✏ But, according to modern concept, Reduction is the chemical reaction in which an atom, ion or molecule gains one or more element. Also known as Electronation.

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$\large{\rm{\red{ Examples}}}$

$\large{\rm{Cl + {e}^{-}\longrightarrow {Cl}^{-}}}$

$\large{\rm{S + 2{e}^{-}\longrightarrow {S}^{2-}}}$

$\large{\rm{MnO_2\longrightarrow {Mn}^{2+}}}$

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Answer 2

Reduction..

Hence option D) is Right