Question

Rene is 6 years older than her young
sister. After 10 years, the sum of their
ages will be 50 years. Find their present
ages.by explaining ​

Answer 1

Answer:

Step-by-step explanation:

Let Rene's younger sister's age =x

Therefore Rene's age=x+6

After 10 yrs age of Rene's sister =x+10

After 10 yrs age of Renee =x+6+10

Given x+10+x+6+10=50

=>2x+26=50

=>2x=50-26

=>2x=24

=>x=24/2

=>x=12

Therefore present age of Rene's sister =12+10=22 and present age of Rene =x+6+10=28

Answer 2

Answer:

Younger sister's age =12 years

Rene's age = 18 years

Step-by-step explanation:

PRESENT AGES

let the age of younger sister =x years

then rene's age =x+6years

AFTER 10 YEARS

younger sister's age = x+10 years

Rene's age = x+6+10 =x+16 years

sum of their ages =50 years

x+10+x+16=50

2x+26=50

2x=50-26

2x=24

x=24/2=12 years

younger sister age =12 years

Rene's age =12+6 =18 years