Question

rene is 6 yrs older than her younger sis after 10 yrs the sum of thier ages will be 50. find thier present ages​

Answer 1

Answer:

Rene age = 18

her younger sister age = 12

Step-by-step explanation:

let Rene present age = x

then her younger sister age = x-6

after 10 year

Rene= x+10

sister= x-6+10 = x+4

according to question

after 10 year sum of there age will be 50

means

(x+10) + (x+4) = 50

x= 18

hence,

Rene present age = 18

her sister age = 18-6 = 12

Answer 2

Answer:

Let Rene's younger sis age be x .

Then Rene age = x + 6

After 10 years ⇒ (x + 6 + 10) + (x + 10) = 50

                       ⇒ (x + 16) + (x + 10) = 50

                       ⇒          2x + 36      = 50

                       ⇒              2x          =   50 - 36

                       ⇒              2x          = 14

                       ⇒               x            =  7

Rene's younger sis age  =  7

Rene age = 13

HOPE ITS HELPFUL

MARK AS BRAINLIEST