Question

Renu is 6years older than her younger sister. After 10years the sum of their ages will be 50 years. Find their ages after 10 years?

Options

1- 15&21
2- 12&18
3- 22&28

Pls answer the following question help me​

Answer 1

✴QUESTION✴

Renu is 6years older than her younger sister. After 10years the sum of their ages will be 50 years. Find their ages after 10 years?

✳SOLUTION ✳

Let, The Present age of younger sister be x.

Present age of Renu be x+6.

After 10 years, Sum of their ages = 50

$\bold{According\:to\:Question}$

$\implies\bold{[(x+6)+10]+(x+10)=50}$

$\implies\bold{(x+16)+(x+10)=50}$

$\implies\bold{2x+26=50}$

$\implies\bold{2x=50-26}$

$\implies\bold{2x =24}$

$\implies\bold{x =\frac{24}{2}}$

$\implies\bold{x=12}$

• Age of younger sister = 12 years
• Age of Renu = 12+6 = 18years

Option (2) is correct.

Hope, This answer will help you!✌

Answer 2

Answer:

Solution

Let's have R be Rene's age.

R

And we have a younger sister who is 6 years younger than Rene:

R−6

In 10 years, the sum of their ages will be 50. So in 10 years Rene will be:

R+10

and her sister will be

R−6+10

and the two added together will be 50:

(R+10)+(R−6+10)=50

How old are they now?

(R+10)+(R−6+10)=50

2R+14=50

2R=36

R=18

and her sister is

R−6=18−6=12

Rene is 18 years now and her younger sister is 12 years now.

Step-by-step explanation:

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