Question

Renu purchases two bags of fertilizer of weights 75 kg and 69 kg. Find the maximum value of weight which can measure the weight of the fertilizer exact number of times.

Answer 1

$\text{For finding maximum weight, we have}$$\text{to find H.C.F of 75 and 69.}$



$\text{Factors of 75 = 3 x 5 x 5 }$



$\text{Factors of 69 = 3 x 69 }$



$\text{H.C.F = 3 }$



$\textbf{Therefore the required weight is 3 kg.}$

Answer 2

Answer:

3 kg.

Step-by-step explanation:

In this problem two bags of fertilizer of weight 75 kg and 69 kg that Renu has purchased.

Now, we have to find the maximum value of weight that is made an exact number of times to measure the weight of the fertilizer.

So, the maximum value of weight will the common factors of 75 and 69.

Now, 75 can be factorized as 3×5×5 and 69 can be factorized as 3×23.

Hence, the common factor is 3.

Therefore, the maximum value of weight is 3 kg. (Answer)