renuka is 12years old. her brother sanjay is 3years older and her mother is 40years old. find the ratio between. (1) renuka age and sanjay age.(2) sanjay and his mother age.
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Given,
Renuka age (R)= 12
Her brother Sanjay's age (S)= 15
( 3 yrs old than renuka)
Mother's age (M)= 40
(1) Renuka's age : Sanjay's age
R:S = 12 : 15 = 4 : 5
(cancel out common factors)
(2) Sanjay's age : His mother's age
S:M = 15 : 40 = 3 : 8
;)
Hope it helps
Renuka age (R)= 12
Her brother Sanjay's age (S)= 15
( 3 yrs old than renuka)
Mother's age (M)= 40
(1) Renuka's age : Sanjay's age
R:S = 12 : 15 = 4 : 5
(cancel out common factors)
(2) Sanjay's age : His mother's age
S:M = 15 : 40 = 3 : 8
;)
Hope it helps
Answered by
4
Given,
Renuka age (R)= 12
Her brother Sanjay's age (S)= 15
( 3 yrs old than renuka)
Mother's age (M)= 40
(1) Renuka's age : Sanjay's age
R:S = 12 : 15 = 4 : 5
(cancel out common factors)
(2) Sanjay's age : His mother's age
S:M = 15 : 40 = 3 :8
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