Math, asked by HARSHKUMARSINGH4796, 10 months ago

Replace# in the number 45#782 by the smallest possible digit so that the number formed is divisible by6

Answers

Answered by kmpartha
0

Answer:

1

Step-by-step explanation:

For a number to be divisible by 6, it needs to be divisible by 2 and 3.

Since this number is already divisible by 2, we have to make the given number divisible by 3.

Divisibility Rule of 3: The sum of the digits of the number should be divisible by 3.

4+5+#+7+8+2 = multiple of 3

4+5+#+7+8+2 = 0, # is negative, hence not applicable.

4+5+#+7+8+2 = 3, # is negative, hence not applicable.

4+5+#+7+8+2 = 6, # is negative, hence not applicable.

4+5+#+7+8+2 = 9, # is negative, hence not applicable.

4+5+#+7+8+2 = 12, # is negative, hence not applicable.

4+5+#+7+8+2 = 15, # is negative, hence not applicable.

4+5+#+7+8+2 = 18, # is negative, hence not applicable.

4+5+#+7+8+2 = 21, # is negative, hence not applicable.

4+5+#+7+8+2 = 24, # is negative, hence not applicable.

4+5+#+7+8+2 = 27

9+10+7+#=27

26+#=27

#= 27-26

#=1

451782 is divisible by 6.

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