Represent √13 on number line
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this is the write answee
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Steps :
• Draw a line segment AB such that AB = 13 cm.
• Then extend AB to a point C where AC = 14 cm.
• Draw the perpendicular bisector of AC , then mark that point as D. (Such that AD = 7 cm and DC = 7cm)
• From point D , draw a semi circle.
• Draw a perpendicular from B in the vertical direction.
Here the distance of point B to that of the semicircle is √13.
• With the help of ruler of compass, trace that distance and denote the distance on number line.
Verification -
Take those perfect square roots which are nearer to it.
i.e. √9 and √16 , Here √9 = 3 and √16 = 4.
So √ 13 must lie near to √ 16 because √13 0= 3.6 (approximately)
And our solution is also same like it.
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