Math, asked by samoghatejas, 1 year ago

Represent 49 using 2,3,5 ?(use only sum and multiplication and twice a number only and the number given to you is 1 as initial number

Answers

Answered by Swarup1998
0

49 = (1 + 3 + 3) × (2 + 5)

Step-by-step explanation:

We have to express 49 with algebraic operations - sum and multiplication among the numbers 2, 3 and 5, also taking 1 as the initial number in the expression.

We have found,

49 = (1 + 3 + 3) × (2 + 5)

Confirmation of conditions:

• 1 as the initial number.

• Using sum and multiplication.

• One number used twice, which is 3.

Thus confirmed.

Answered by amitnrw
3

Represent 49 using 2,3,5

((1 + 3 )* 5 + 2 ) * 2 + 5 = 49

Step-by-step explanation:

Solution :

1 + 3  * 5  + 2  * 2  + 5   ( do not apply Bodmas here , solve in the sequence as terms come)

written with brackets for  better Clarification

((1 + 3 )* 5 + 2 ) * 2 + 5 = 49

= ( 4 * 5 + 2) * 2 + 5

= (20 + 2) *2 + 5

= 22 * 2 + 5

= 44 + 5

= 49

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