Question

a stone is thrown vertically upwards with an initial velocity of 98m/s . 4seconds later another stone is thrown upwards with the same velocity . find the distance between the two stones , when the velocity of the first stone become zero​

Answer 1

Answer:

first of all you need to find maximum height attained by the stone one by using kinematics formula and then you need to find time under which stone when reaches its maximum height which comes out to be as 10 seconds and then you need to subtract 4 second from this to get time under which stone 2 moves under which time interval stone one attendance zero velocity and then you need to find distance travelled by stone two in this time and to find distance between these two stone you need to subtract height attained by stone 1 and height attained by stone to in their respective Times