represent √5 on number line
Answers
♡ Heya buddy ♡
⚫Follow these steps :-
1. Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents
2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.
2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.We have OA=2 units and AB=1unit.
Using pythagoras theorem, we have,
OB^2 = OA^2 + AB^2
➱OB^2 = 2^2 +1^2
➱OB =√5
Taking O as the centre and OB= √5 as radius draw an arc cutting real line at C.
Clearly, OC=OB= √5
Hence, C represents √5 on the number line.
✧ Thanks ✧
Answer:
Step-by-step explanation:
If possible, let √5 be rational and let's it's simplest form a/b.
√5=a/b
5=a²/b²
5b²=a²
5 divides a² ( 5 divides 5b²)
5divides a
Now,
Let a=5c for some integer c.
Putting a=5c in (i), equation
We get,
5b²=25c²
b²=5c²
5 divides b² ( 5 divides 5c²)
5 divides b
5 is a common factor of a and b.
The contradiction arises by assuming that √5 is rational
Hence, √5 is irrational.
I hope you understand