Question

Represent in the form of quadratic equation (x – 5) (x + 4) = (x + 1) (x + 2) – 2x

2

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Answer 1

Step-by-step explanation:

(x-5) (x+4) = (x+1) (x+2) - 2x^2

open the brackets by multiplying the terms within the brackets

{x^2 + 4x -5x -20} = {x^2 + 2x +1x + 2} - 2x^2

x^2 - 1x - 20 = x^2 + 3x + 2 - 2x^2

x^2 - 1x - 20 = -1x^2 + 3x + 2

moving all numbers to LHS, we get

x^2 - 1x -20 + 1x^2 - 3x - 2 = 0

2x^2 - 4x - 22 = 0

2 (x^2 - 2x - 11 ) = 0

x^2 - 2x - 11 = 0/2

x^2 - 2x -11 = 0

Answer 2

Answer :-

(x-5) (x+4)=(x-1)(x+2)-2x²

• x²+4x²-5x-20= (x²+2x+x+2)-2x²
• x²-x-20=x²+3x+2-2x²
• x²-x-20=x²+3x+2-2x²
• x²-x-20+x²-3x-2=0
• 2x²-4x-22=0
• 2(x²-2x-11)=0
• (x²-2x-11)=0

Therefore the quadratic equation is (x²-2x-11)=0