represent root 2.7 on number line
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- Draw a line of 2.7 CM AB
- extend line to BC 1 CM
- then mark the center of AC as O
- take radius as OA and draw a semi circle
- draw a perpendicular bisector of OC mark point as D
- take radius of BD and draw a semicircle to E
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Answer:
Heya buddy.......
1.Draw a line of 2.7 cm & name it AB.
Therefore, AB = 2.7 cm
2.From B again draw a line of 1 cm & name it C
Therefore, BC = 1 cm
3.Then find the centre of A & C through perpendicular bisector.
4. Name the centre as O. Then with O as centre & AO or OC as radius draw a semicircle.
5. Now draw 90° on B such that it should intersect the semicircle at point D.
6.Hence, BD = √2.7
7.With B as centre & BD as radius draw an arc interesting the number line & name the point F.
8.And lastly, F represents √2.7 on the number line.
Hope it’s helpful...... ☺
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