Question

Represent the cell from the following given reaction ЗNi + 2A (1) 3NI " (1M) + 2 AL​

Answer 1

Answer:

Mark me in the brain list , (•ө•)

Explanation:

Mg+2Ag+(0.0001M)⟶Mg2+(0.130M)+2Ag

Ecell=Eo−20.0591log[(Ag+)2(Mg2+)]

Ecell=8.17−20.0591log[10−80.130]=2.959 V

Answer 2

Answer:

The cell reaction in terms of cell notation is

Mg∣∣Mg2+(0.130M)∣∣∣∣Ag+(0.001M)∣∣Ag

Ecell=E∘cell−0.0591nlog[Anode][Cathode]

=(3.17)−0.05912log0.130(0.0001)2=(3.17)−0.05912log0.05912log0.13010−8

=(3.17)−0.02955 log (1.3×107)=(3.17)−(0.02955×7.1139)

=(3.17−0.21)=2.69V.

Hope it helps u !!