Math, asked by bistudas1979gmailcom, 3 months ago

represent the following equation graphically F=(9by5)C+32 who will answer this question i will make them brainlist​

Answers

Answered by mathdude500
3

\large\underline\purple{\bold{Solution :-  }}

\tt \:  Equation  \: of  \: line  \: is  \: F = \dfrac{9}{5} C + 32 -  -  - (1)

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\large\underline{\bold{❥︎Step :- 1 }}

\tt \:  ❶ Substituting 'C = 0' in  \: the \:  equation,  \: we  \: get</p><p>

\tt \:  ⟼ \: F = \dfrac{9}{5}  \times 0 + 32 = 32

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\large\underline{\bold{❥︎Step :- 2 }}

\tt \:  ❷ Substituting 'C =  - 5' in \:  equation \: (1),  \: we  \: get

\tt \:  ⟼ \:  \: F = \dfrac{9}{5}  \times ( - 5) + 32

\tt \:  ⟼ \:  \: F =  -  \: 9 + 32 \:  = 23

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\large\underline{\bold{❥︎Step :- 3 }}

\tt \:  ❸ \:  Substituting 'C =  - 10' in \:  equation \: (1),  \: we \:  get

\tt \:  ⟼ \: F = \dfrac{9}{5}  \times ( - 10) + 32

\tt \:  ⟼ \:  \: F =  - 18 + 32 \:  =  14

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☆ Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

\begin{gathered}\boxed{\begin{array}{c|c} \bf C &amp; \bf F \\ \frac{\qquad \qquad}{} &amp; \frac{\qquad \qquad}{} \\ \sf 0 &amp; \sf 32 \\ \\ \sf  - 5 &amp; \sf 23 \\ \\ \sf  - 10 &amp; \sf 14 \end{array}} \\ \end{gathered}

➢ Now draw a graph using the points (0 , 32), (-5 , 23) & (-10 , 14)

➢ See the attachment graph.

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