Question

Represent the following measurements by using suitable SI prefixes(i) 2 × 10–8 s (ii) 1.54 × 10–10 m (iii) 1.98 × 10–6 mol (iv) 200 000 kg

Answer 1

Answer:

Explanation:

Using Suitable of these

p = pico = 10⁻¹²

n = nano =  10⁻ⁿ

μ  = micro = 10⁻⁶

m = milli = 10⁻³

k = kilo = 10³

M = mega = 10⁶

G = Giga = 10⁹

T =  Tera = 10¹²

2 × 10–8 s

= 2 * 10 * 10⁻⁸/10

= 20 * 10⁻⁹ s

= 20 ns

1.54 × 10–10 m

= 1.54 * 100 * 10⁻¹⁰/100 m

= 154 * 10⁻¹² m

= 154 pm

1.98 × 10–6 mol

= 1.98 μmol

200 000 kg

= 200 * 10³  kg

= 200 Mg

Answer 2

Answer:

Answer:

2 × 10–8 s

= 2 * 10 * 10⁻⁸/10

= 20 * 10⁻⁹ s

= 20 ns

1.54 × 10–10 m

= 1.54 * 100 * 10⁻¹⁰/100 m

= 154 * 10⁻¹² m

= 154 pm

1.98 × 10–6 mol

= 1.98 μmol

200 000 kg

= 200 * 10³  kg

= 200 Mg