represent the form of quadratic equation (x-5) (x+4)=(x+1) (x+2)-2k^2
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( x - 5 ) ( x + 4 ) = ( x + 1 )( x + 2 ) - 2k^2
( x - 5 ) x + ( x - 5 )4 = ( x + 1 )x + ( x + 1 )2 - 2k^2
x^2 - 5x + 4x - 20 = x^2 + x + 2x + 2 - 2k^2
x^2 - x - 20 = x^2 + 3x + 2 - 2k^2
x^2 - x^2 + 2k^2 - x - 3x - 20 - 2 = 0
2k^2 - 4x - 22 = 0
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( x - 5 ) ( x + 4 ) = ( x + 1 )( x + 2 ) - 2k^2
( x - 5 ) x + ( x - 5 )4 = ( x + 1 )x + ( x + 1 )2 - 2k^2
x^2 - 5x + 4x - 20 = x^2 + x + 2x + 2 - 2k^2
x^2 - x - 20 = x^2 + 3x + 2 - 2k^2
x^2 - x^2 + 2k^2 - x - 3x - 20 - 2 = 0
2k^2 - 4x - 22 = 0
✌
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Answer:
here is ur answer nd best of luck
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