Question

Represent the galvanic cell in which the reactions is
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s) [Delhi 2013(C)]

Answer 1

Answer:

this is the answer of your

Answer 2

Answer:

written below-

Explanation:

) The reaction given is: Zn(s)+Cu2^{+} (aq) >Zn^{2+}(aq)+Cu(s)

2) From that, you can see the Zn(s) is loosing the electron since it is being oxidized (from 0 to 2^{+}) while Cu^{2+} isgaining electrons, since it is beingreduced (from 2 to 0)

3) Then, you can already tell thatelectrons go from Zn to Cu

4) The plate where oxidation occurs iscalled anode, and the plate wherereduction occus is called cathode`

So you get that the electrons flowfrom the anode (Zn) to the cathode(Cu).Always oxidation occurs at theanode, and reduction occurs at the cathode.

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