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Find a quadratic polynomial with 0,75 as the sum and product of its zeroes respectively.
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1
Answer:
Given,
Sum of roots =
4
1
Product of roots =−1
P(x)=x
2
−(sum−of−roots)x+(product−of−roots)
=x
2
−
4
1
x−1
∴4x
2
−x−4=0
is the required differential equation
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