Question

Requirements to determine no. Of microorganisms by using heamocytomeyer

Answer 1

Answer:

✔✔ If the cell counts for each of the 16 squares were 50, 40, 45, 52, the average cell count would be: (50 + 40 + 45 +52) ÷ 4 = 46.75. 46.75 x 10,000 (104) = 467,500. 467,500 x 5 = 2,337,500 live cells/mL in original cell suspension. ✔✔