Question

reset answer
6
Determine the value of (a+b+c)/(a+b-c) for the following expression to be true
a/2=b/5=c/6​

Answer 1

Answer:

13

Step-by-step explanation:

Let a/2 = b/5 = c/6 = k

→ a = 2k, b = 5k, c = 6k

Therefore,

=> (a + b + c)/(a + b - c)

=> (2k + 5k + 6k)/(2k + 5k - 6k)

=> (13k)/(k)

=> 13/1

=> 13

Answer 2

Answer:

✰ Given :-

• $\dfrac{a}{2}$ = $\dfrac{b}{5}$ = $\dfrac{c}{6}$

✰ To Find :-

• What is the value of $\dfrac{(a + b + c)}{(a + b - c)}$

✰ Solution :-

➔ Let, $\dfrac{a}{2}$ = $\dfrac{b}{5}$ = $\dfrac{c}{6}$ = k(say) [ k ≠ 0 ]

» Then, we get a = 2k, b = 5k, c = 6k

➣ According to the question,

:$\implies$ $\dfrac{(a + b + c)}{(a + b - c)}$

↬Putting the value we get,

:$\implies$ $\dfrac{(2k + 5k + 6k)}{(2k + 5k - 6k)}$

:$\implies$ $\sf\dfrac{13\cancel{k}}{\cancel{k}}$

:$\implies$ $\dfrac{13}{1}$

:➠ 13

$\therefore$ The value of $\dfrac{(a + b + c)}{(a + b - c)}$ is $\boxed{\bold{\large{<u>1</u><u>3</u>}}}$

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