Question

resistance of 0.1 normality KCL solution was found to be 62 on at 298 Kelvin calculate the conductivity and equivalent conductivity of salt solution​

Answer 1

N=0.1N

R=62

C=1/R

C=1/62

C=0.0161

^c=K×1000/N

I order to find the value of k we need resistivity or the values of cell constant

I hope this helps ( ╹▽╹ )