Question

Resistance of 10 m long wire is of petentiometer is 10ohm/m a cell of 2.2 v emf and high resistance box in series with the wire how much resistance must be appl;ied to get 2.2 v of mv/mt gradient

Answer 1

potentiometer resistance = 10*10= 100 ohm

0.022= 2.2-(2.2R)/(100+R)

solving we get R=9900ohm